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Specialty Chemistry Forums => Other Sciences Question Forum => Topic started by: DeadlyGreenWalrus on October 12, 2005, 10:15:57 AM

Title: Equation for Pb(NO3)2(aq) + H2SO4(aq)
Post by: DeadlyGreenWalrus on October 12, 2005, 10:15:57 AM

a chemistry question in my homework. This part is not
very important, as the question acctually asks what
volume of lead nitrate will react with 50cm3 of
0.1moldm-3 sulphuric acid. I have the answer to the question
but i just wanted to check that my formula was correct!

This is the Formula:-
Pb(NO3)2(aq) + H2SO4(aq) --> PbN2S + 2H2O(l) + 3O2(g)

Thak you

Title: Re:Equation for Pb(NO3)2(aq) + H2SO4(aq)
Post by: jdurg on October 12, 2005, 11:05:04 AM

Hmmmm....  What's N2S?   ;)  In order for that compound to exist, you'd have to have Sulfur and nitrogen in oxidation states that just do not work.  You'd also need to break down the NO3(-) ion as well as the SO4(2-) ions.  You simply don't have a strong enough oxidizer to break apart those ions.  With the solutions being dilute, what you'll wind up with is a simple double displacement where PbSO4 ppts out and a solution of weak nitric acid is left.