Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: DaiseyDoo on August 02, 2015, 06:34:42 PM
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In iodination of salicylamide, NaI and salicylamide are mixed for a while first and cooled to 0C before NaOCl is added. I'm wondering why it must be cooled before the reaction proceeds?
NaOCl is added to react with NaI and form electrophilic Iodine.
My only reasoning is that when NaOCl reacts with NaI it's highly exothermic so the reaction has to be cold for it to be "safe".
Thanks in advanced!
Procedure on 3rd page:
http://www.mycrandall.ca/faculty/mschriver/lectures/ch1023w09/exp17greeneasstd.pdf