We are doing a project in school in which we must make 2.0 grams of CaSO4 in a double displacement reaction. Our reaction is FeSO4+CaCl2=FeCl2+CaSO4
We have decided that we need 2.23g FeSO4 and 1.63g CaCl2
Our real problem is that we need to make a procedure without being able to actually test it first. This is what we have so far, not really sure if it will work.
Materials
1 100ml Beaker
2 Erlenmeir(spelling?) Flasks
1 50ml graduated cylinder
1.63g CaCl2
2.23g FeSO4
Filter Paper
Glass Funnel
Procedure
1.) Dissolve 1.63g CaCl2 in 50ml of water in a flask.
2.) Dissolve 2.23g FeSO4in a separate beaker of 50ml of water.
3.) Pour both solutions into another beaker and mix.
4.) Filter the solution to retrieve the CaSO4
This is the equation we have.
1.63g CaCl2+2.23gFeSO4=2.00gCaSO4=1.93gFeCl2
We need as close to 2.0g CaSo4 as possible.
We have no way of testing if this will work. We aren't sure how to mix it, or what will be filtered out, whether it is FeCl2 or CaSO4.
We would like help on our procedure as we can't actually test it. Thanks in advance.