[ILoveISO]

Did I do this correct? Question asks me to caculate the exact molarity of unknown diprotic acid.

I took the initial ph of the acid when no NaOH has been added yet (2.09) and 10^(-2.09) = ph and got 0.0081M is that right?

If so the next questions asks

"Using the given concentration of the unknown diprotic acid calculate its exact molar mass"

Given conc = 8.013g/L

I did 8.013/0.0081M = 985g... is this right?

[Borek]

I took the initial ph of the acid when no NaOH has been added yet (2.09) and 10^(-2.09) = ph and got 0.0081M is that right?

You have not listed informatin that you have, so nobody will be able to help. One thing is clear - this is wrong. If this is a strong acid - it is diprotic, so its concentration is different from what you have calculated. If it is a weak acid - it is not fully dissociated, so its concentration is different from what you have calculated.

You wrote something about adding NaOH. So perhaps that's just a titration question.

[ILoveISO]

Yes this is a titration question, I used NaOH to titrate 25ml of unknown diprotic acid

[Borek]

So this is a simple stoichiometry to find number of moles and later molar mass.

[ILoveISO]

Care to guide me thru it if it's so simple. I don't have a balanced equation and I don't even know what the unknown is how am I going to use stoich...

[ILoveISO]

I do not have the molarity of NaOH and the acid is an unknown so I have no balanced equation, how am I supposed to do it if it's so simple.

[Borek]

Give FULL question with ALL data you are given. You are wasting our time asking partial questions which lead nowhere.