[Gobess]

Hi    everyone this is my first post here hope you guys could help me out.

2Na + Cl2 results in 2NaCl

(A) How many moles of Cl2 are needed to react with 3.5 moles of Na?

(B) How many grams of NaCl are produced from 1.75moles of Cl2?

(C) What weight of Na is required to produce 73.11g NaCl ?



My attempt :

(A) Since there are 2 moles of Na and 1 mole of Cl and Na has 3.5moles I just cross multiplied and got 1.75moles for Cl2.

(B) First I got the grams of Cl2 by multiplying 1.75moles by 71g/mol (2 chlorine's) I got 124.25grams. I then cross multiplied with the moles of of NaCl (3.5) and Cl2 (1.75) with the 124.25 grams of Cl2. I got 248.5 grams.

(C) The weight got me confused. I just found out the NaCl's mole and since it has 2 and Na has 2 I just put that number I got and multiplied it by the atomic mass of Na and got 28.74grams since they want weight I just multiplied it by 10. 287.4N.


(I know this question might seem simple but I really need help figuring out how to tackle these types of questions)
(sorry for having 3 questions but they are all related to each other)

THANKS

[Borek]

(B) First I got the grams of Cl2 by multiplying 1.75moles by 71g/mol (2 chlorine's) I got 124.25grams. I then cross multiplied with the moles of of NaCl (3.5) and Cl2 (1.75) with the 124.25 grams of Cl2. I got 248.5 grams.

No, you got it wrong and to be honest, I have a hard time following what you did.

How many moles of NaCl produced?

(C) The weight got me confused. I just found out the NaCl's mole and since it has 2 and Na has 2 I just put that number I got and multiplied it by the atomic mass of Na and got 28.74grams since they want weight I just multiplied it by 10. 287.4N.

My bet is that they want the answer in everydays sense - that is, 28.7g will do.

Watch significant numbers.

[Gobess]

Thanks