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Topic: Gold Cyanidation  (Read 2560 times)

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Offline Boxxxed

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Gold Cyanidation
« on: April 24, 2011, 03:32:48 AM »
In gold mining , cyanide solutions are often used to dissolve AuBr from ore samples.  In the presence of cyanide ions, CN-, gold forms a soluble complex according to the following reaction:   Au+ + 2CN- ↔ Au(CN)2-.  The formation of this complex causes the AuBr in the ore to dissolve.  The Au(CN)2- complex has a Kform = 2.0x1013 and the Ksp of AuBr is 5.0x10-13.


Would this be the correct net reaction?
AuBr-->Au + Br
Au + 2CN-↔ Au(CN)2

AuBr+2CN---Au(CN)2+Br

Offline rabolisk

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Re: Gold Cyanidation
« Reply #1 on: April 24, 2011, 04:06:31 AM »
That's confusing. Please don't neglect charges on ions.

Offline Boxxxed

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Re: Gold Cyanidation
« Reply #2 on: April 24, 2011, 01:44:32 PM »
AuBr ↔ Au + + Br-
Au + + 2CN- ↔ Au(CN)2

AuBr + 2CN- ↔ Au(CN)2 + Br-

Should be good now, this is correct?
« Last Edit: April 24, 2011, 02:16:14 PM by Boxxxed »

Offline rabolisk

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Re: Gold Cyanidation
« Reply #3 on: April 24, 2011, 04:55:16 PM »
No. Charge is not balanced.

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