I cannot figure this problem out, or how to find mL of the base need. It's a 1:1 ratio I believe, so how do I go from here?
10.6= 10.63 + log x /[.353-x]
-0.03 = log x / (.353-x)
.933 = x / .353 - x
.933 (.353-x) = x
.329 - .933x = x
.329 = 1.933x
x= .170
Do I need to do anything with the original volume of the acid?
Perhaps, C1V1= C2V2??