[Rafiq]

I am having that hardest time balancing this equation.  can you help me?

1. The reaction between potassium permanganate, sulphuric acid and oxalic acid produces manganese (II) sulphate, potassium sulphate, water and carbon dioxide.  Write a complete balanced equation and a net ionic equation for this reaction.

i did the equation, but i am having troubles balancing it.

Balanced equation:

KMnO₄  + H₂SO₄ + C₂H₂O₄  --------->k₂SO₄ + Mn₂SO₄ + H₂O+ CO₂

[Will]

Hi!

I think that manganese (II) sulfate has the formula MnSO₄ and to balance that it would be:

2KMnO₄ + 3H₂SO₄ + 5C₂H₂O₄ ---> K₂SO₄ + 2MnSO₄ + 8H₂O + 10CO₂

Hope that helps!

[sdekivit]

yes --> Mn-ions are (2+) so manganesulphate = MnSO4

[Rafiq]

Hi!

I think that manganese (II) sulfate has the formula MnSO₄ and to balance that it would be:

2KMnO₄ + 3H₂SO₄ + 5C₂H₂O₄ ---> K₂SO₄ + 2MnSO₄ + 8H₂O + 10CO₂

Hope that helps!

Thanks alot you guys, really appreciate it.

how do you do net ionic equation for this:



KMnO₄  + H₂SO₄ + C₂H₂O₄  --------->k₂SO₄ + Mn₂SO₄ + H₂O+ CO₂

[Rafiq]

How i do a net ionic equation for this?

2O₄ + 2H₂ + 5C₂ + 5H₂ + 50₄ -------> 8H₂0 + 10CO₂

[Will]

For the ionic equation you write out the equation like this:

2K⁺ + 2MnO₄^- + 6H⁺ + 3SO₄^2- + 5C₂H₂O₄ ---> 2K⁺ + 2Mn²⁺ + 3SO₄^2- + 8H₂O + 10CO₂

then you cancel out the same species to get the net ionic equation:

2MnO₄^- + 6H⁺ + 5C₂H₂O₄ ---> 2Mn²⁺ + 8H₂O + 10CO₂

I haven't done this for ages so I hope thats right- you may have to write C₂H₂O₄ as C₂O₄^2- + 2H⁺

The second equation doesn't really make sense: to get O₄ you have to compress oxygen to a pressure of 200 billion Pascals (almost 200000 atm).

[Borek]

For balancing and checking reaction equations - take a look at EBAS.

As for oxalic acid - in acidic conditions needed for this reaction, it will be almost completely protonated, thus it will be (COOH)₂ (or C₂H₂O₄ if you prefer).