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Topic: Calculating equilibrium constants and heat of dissociation  (Read 5775 times)

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Offline kimi85

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Calculating equilibrium constants and heat of dissociation
« on: June 28, 2007, 09:47:48 PM »
At constant pressure of 1 atm, N2O4 is 50% dissociated at 60 degree C, and 79% at 100 degree Celsius.  Calculate the equilibrium constantat these temperatures for the reaction N2O4 = 2NO2.

This is what I did but I didn't get the right answer:

I find the delta G using the values found at the table. I multiplied each to the number of moles during the dissociation, then product minus the reactant
so, my delta G at 60C is 2365 J.  Then I used delta G = -RTlnK
I got 0.4256, but the correct answer is 1.33

For the delta H, I used delta G = delta H - T deltaS
but I my answer is still wrong.  The correct answer is 41.5 kJ.

Does anybody know what's wrong with my solution?
Thank you very much!

Offline Borek

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Re: Calculating equilibrium constants and heat of dissociation
« Reply #1 on: June 29, 2007, 02:47:12 AM »
If you know how much gas is dissociated simple stoichiometry allows calculation of equilibrium concentrations, put them into reaction quotient and you are done. No need for delta G tables.
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Offline kimi85

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Re: Calculating equilibrium constants and heat of dissociation
« Reply #2 on: June 29, 2007, 03:26:59 AM »
Thank you sir. ;D

I'll try it.

Offline Yggdrasil

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Re: Calculating equilibrium constants and heat of dissociation
« Reply #3 on: June 29, 2007, 05:58:51 PM »
The information in the tables is usually for either 0oC or room temperature.  You are asked to find the value at 60oC, which will be different from the value at other temperatures.

Offline kimi85

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Re: Calculating equilibrium constants and heat of dissociation
« Reply #4 on: June 30, 2007, 06:32:33 AM »
Thank you for that information. :)

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