the formula for freezing point depression is:
delta Tf = Kf * cm * i
i = 1 since there is no dissociation ( van 't Hoff's factor)
delta T = 28,888888889 degrees C and the cryoscopic constant of water is -1,86 degrees C / molal.
So we get:
-28,888888889 = -1,86 * cm which leads to a molal concentration of 15,53166069 molal ethylene glycol.
this means that there is 15,53166069 mol ethylene glycol / kg water. We know that 1 L water weighs 1 kg so we need 15,53166069 mol ethylene glycol
that's 15,53166069 * 62,068 = 964,0191157 g ethylene glycol and that's 964,0191157 / 1,11 = 8,7 x 102ml ethylene glycol.