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Topic: Hybridization in Ethylene  (Read 3962 times)

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Offline susdujcrd

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Hybridization in Ethylene
« on: March 23, 2012, 08:20:36 AM »
I understand that the Carbon atom in C2H4 undergoes an sp2 hybridization,
taking one 2s orbital with two half-filled 2p orbitals to create three sp2 orbitals.
Why the newly arranged electrons occupy the third empty 2p orbital as well? isn't it of higher energy than the three new sp2 obritals?

Offline AWK

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Re: Hybridization in Ethylene
« Reply #1 on: March 23, 2012, 08:56:15 AM »
There is no empty 2p orbitals in ethylene. One electron at each C occupy  this orbital forming pi-bond.
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Offline susdujcrd

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Re: Hybridization in Ethylene
« Reply #2 on: March 23, 2012, 09:05:50 AM »
the pi-bond comes from the overlapping of the remaining 2p orbital in each of the carbons.


Offline AWK

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Re: Hybridization in Ethylene
« Reply #3 on: March 23, 2012, 09:12:55 AM »
Exactly!
This are two different problems - isolated (or excited) atom and atom in molecule
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Offline susdujcrd

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Re: Hybridization in Ethylene
« Reply #4 on: March 23, 2012, 09:42:25 AM »
I think I got it, thank you.

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