Ok from magician4's equation for the equivalence point I gather that both NH3 and NaOH are to be seen as bases and n
0(NaOH) reaches the point where the equation is satisfied, at the equivalence point. n
0(NaOH) for Solution 3, at the equivalence point, is given. n
0(H2SO4) (for Solutions 2 & 3) is given. n
0(NH3) is then calculated from the other two, for all 3 Solutions.
So now we just set up mass balance, charge balance and equilibrium equations for each of the three situations and solve them for [H
+]? Well that's the exact (and un-insightful) method anyway. I tried this for the first solution, Solution 1, with only n
0(NH3) present. It worked. This leads me to think it would work for the others as well.
So what method might we follow which would enable us to solve it for Solution 1, at least, without needing to handle a cubic or higher order equation?
I'm talking about approximations