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Topic: Equilibrium Calculations:  (Read 1603 times)

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Offline blahh

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Equilibrium Calculations:
« on: February 20, 2012, 02:47:47 PM »
The substance AO2 (aq) is 10% molar (Mol/L) dissociated as follows:
4AO2(aq) <--> A2O3(aq) + O2(aq)

How many moles of each component will be present in the mixture at equilibrium, if 2.00 mols of A2O3 and 1.00 mols of O2 are present initially in a container of 1.00 L.

I don't understand how I can calculate the values when I have nothing to work with... Can you please explain thank you so much.
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Offline Borek

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Re: Equilibrium Calculations:
« Reply #1 on: February 20, 2012, 03:19:17 PM »
Use 10% dissociation information to calculate equilibrium constant. To make things easier assume you started with 1 mole of AO2 - after 10% reacted, how much A2O3 and O2 would be present?
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