in the reaction 10mL of 1M NaOH + 5mL of 1M HCl (adiabatic)
given change in temp=2.1°C (temp initial is the temp of NaOH, temp final is acquired after the addition of HCl)
find: qrxn, qcal, Ccal
i used the molarity to find the number of moles for each reactant. i think i should use the equation: dh=qrxn/nrxn but i don't know what nrxn means. is it the total number of moles?
0.01mol (NaOH) + 0.005(HCl) = 0.015mol = nrxn? is this correct?
given dH formation of water=-55.8kJ/mol
help please. thanks in advance:)