May 20, 2024, 07:36:40 AM
Forum Rules: Read This Before Posting


Topic: Calculating pH of solution  (Read 4810 times)

0 Members and 1 Guest are viewing this topic.

Offline munoz_m1

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-1
Calculating pH of solution
« on: March 19, 2008, 08:50:31 PM »
The question is:
Calculate the pH of each of the following solutions:
(1) A sample of seawater that has an OH- concentration of 1.58 x 10-6 M

So I came up with: pH=14 for the first question but I can't figure out the second part of the question which is:

(2) A sample of acid rain that has an H3O+ concentration of 6.0 x 10-5 M.

[I follow example questions in my text book to help guide me through practice problems, but in my book I can't figure the second question because the book uses OH problems.]

Offline Arkcon

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7367
  • Mole Snacks: +533/-147
Re: Calculating pH of solution
« Reply #1 on: March 19, 2008, 09:08:37 PM »
Does you answer to number one really seem plausible to you?  You think seawater is stronger than oven cleaner?  Remind me not to go swimming where you go. ;)

OK, let's see the formula you're using, you may have gotten it backwards.
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

Offline flightman233

  • Regular Member
  • ***
  • Posts: 26
  • Mole Snacks: +1/-0
Re: Calculating pH of solution
« Reply #2 on: March 22, 2008, 08:32:37 PM »
I would definitely go back and recheck your answer for part A.

when you take the -log of [OH-] you get pOH.

pH + pOH = 14.  So 14 - pOH gives you pH.  You should have come up with an approximate value of 5.80 for pOH.  Subtracting from 14 gives you a pH of about 8.2.

Now, the next problem is relatively straight forward just take the -log of [H+].

So -log[6.0X10-5] = 4.22 = pH

hope that helps.

Sponsored Links