Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: eureka123 on October 27, 2009, 10:28:17 PM
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What is the final product ?
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What's LDA act as?
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LDA is a hindered strong base. So basically you have to decide where it will attack i.e. which acidic H it will remove to form the carbanion.
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oh...i know all that ...i have doubts regarding final product....
i am posting two options..tell me which it will be ???
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Are alkyl chains electron donating or withdrawing?
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electron donating..
plz tell me the final answer....
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Remember, you only have 1 eq of LDA, you can only deprotonate your starting material once
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Unless your product has a more acidic proton than your reagant. Is that the case?
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thats what my doubt is....
plz all the experts here reply...
i feel ans should be 2nd option..but ans given in book is 1st option
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Well I'd say you're right and the book is wrong.
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I agree.
It might be a typo in your book.
However, even if some dialkylated material were formed, it would be in mixture with some monoalkylated material.
Unless we think that a rather hindered 1,3-dicarbonyl compound is allylated by an excess of allyl bromide without any base? I don't think so.
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Thanx everyone
but
Unless your product has a more acidic proton than your reagant. Is that the case?
plz explain why the above situtation with an example if possible
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If trifluoromethane was your substituent, that would increase the acidity of the remaining proton.
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ok ..tahnx everyone for your contributions...
such thpe of sicussion help a lot :) :)