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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: 98offroadZR2 on January 25, 2006, 07:08:20 PM

Title: a ceramic contains 23 mol% MgO and the rest silicon dioxide
Post by: 98offroadZR2 on January 25, 2006, 07:08:20 PM

what is the wt% MgO in the ceramic, what is the mol% Si in the ceramic, what is the O/Si ratio in mol/mol in the ceramic


How do i go about solving this

Title: Re:a ceramic contains 23 mol% MgO and the rest silicon dioxide
Post by: Bakegaku on January 27, 2006, 10:19:56 PM

To find the weight percentage of MgO, you'd look up the molar mass of MgO and then multiply that by the percentage of MgO moles in the ceramic.  (converting percentage into a decimal, of course)  Do the same for SiO, add the numbers, then divide the number you got for MgO by the sum of the two numbers.