Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Nitin_Naudiyal on May 17, 2013, 01:48:49 AM
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I was reading about Leclanche's Cell,
It is mentioned that " The Complexation of Zn2+ by NH3 molecules decreases the concentration of Free Zn2+ ions. This Increases the Voltage of the cell. "
I want to know, how decrease in the concentration of Zn2+ ions increases the voltage of the cell.
Thank you in Advance
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Can you write Nernst equation for the cell?
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Oxidation at Anode:
Zn :rarrow: Zn2+ + 2e-
Reduction at Cathode:
2NH4+ + 2MnO2 + 2e- :rarrow: Mn2O3 + 2NH3 + H2O
Net Cell Reaction:
Zn + 2NH4+ + 2MnO2 :rarrow: Zn2+ + Mn2O3 + 2NH3 + H2O
Nernst Equation:
Ecell = E0 - 0.0592/2 Log([Zn2+][NH3]2[H2O]/[NH4+]2)
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Ecell = E0 - 0.0592/2 Log([Zn2+][NH3]2[H2O]/[NH4+]2)
Assuming everything else doesn't change and rearranging:
[tex]E' = -\frac{0.0592}{2} \log([Zn^{2+}]) = \frac{0.0592}{2} pZn[/tex]
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So, as the Concentration of Zn ions decreases, the value of the non standard state electrochemical condition in the Nernst Equation decreases and hence the value of Ecell increases i.e. Potential of the cell increases.
Am i correct ?
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Yes, we are dealing with a formal potential.
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Thank You for your Help