[murphetron]

Hydrogen fluoride, HF, can be made from the reaction
H2+ F2 2HF
In one experiment, 0.10 mol of H2 and 0.050 mol of F2 are introduced into a 0.50 L container.
At equilibrium there is 0.01 M of F2 present. Calculate the Kc for this reaction.

H2-0.1/0.5=0.2, F2-0.05/0.5=0.1..Change 0.01/0.5= 0.02...at equilibrium- H2= 0.02, F2= 0.08, HF= 2(0.02)=0.04
[0.04]Λ2
[0.08][0.02]=1 mole

[Borek]

You have to show your attempts at solving the question to receive help. This is a forum policy.

Think if you can't calculate amounts of other substances from the stoichiometry.

[kittyyang]

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[iamback]

Try recalling the formula for K_c and try again.