[science fan]

I am having trouble with a question below:

Magnesium reacts with dilute hydrochloric acid:
I wrote the equation as:
 Mg_(S)+ 2H⁺ _(aq):Mg_(aq)+H₂(g)
If 0.720 g of magnesium is treated with 0.950 mol L ^-1of hydrochloric acid calculate the:
(a) The volume of hydrocholric acid needed to react with all the magnesium


What I did for a was use the mole statment and the formula n=m
                                                                                    M
and the n= V
             22.4

However I got the answer incorrect because I think I used the wrong forumals.
What are the steps to calculate the volume of HCL

Thank you

[lythuyvy]

Mg(S)+ 2H+ (aq):Mg(aq)+H2(g)
->Mg2+

[science fan]

sorry but that is not the answer I was looking for.

[lancenti]

Mg (s)+ 2H⁺ (aq) ->  Mg²⁺ (aq) + H₂ (g)

If 0.720 g of magnesium is treated with 0.950 mol L^-1of hydrochloric acid calculate the volume of hydrocholric acid needed to react with all the magnesium.

According to the equation, I need 2 mol of Hydrochloric Acid per mole of Magnesium. There's no need to use any special formulae, since they're not asking you for Hydrogen Chloride "HCl (g)", but rather Hydrochloric Acid "HCl (aq)".