Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Organic Chemistry Forum for Graduate Students and Professionals => Topic started by: kea1118 on March 28, 2017, 09:50:33 PM
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Hi All,
I've been trying to work out the mechanism for the following step in the synthesis of Imatinib. I would greatly appreciate any tips on how the mechanism begins or if there are any sources online that show a reaction mechanism somewhat like this.
Thank you in advance for your help,
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I feel strongly that there are other reagents in this. Or at least a solvent.
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I feel strongly that there are other reagents in this. Or at least a solvent.
Are you sure? It's an ortho amide, which has a higher transition state than tetrahedral intermediates between immines and aldehdyes. The 2 methoxy anions are the 2 eq of base required to start the reaction. It seems like one less thing to do if you are already gonna distill the orhto acid dry.
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Is the alpha hydrogen acidic enough with just the DMF-DMA to be deprotonated to form the carbanion? That's where I'm getting lost. I got the picture from synthesis pathway Pharmaceutical Substances. There was a mistake in the esomeprazole one so it is possible that maybe a solvent is missing because I don't think the methoxy ion would be a strong enough base to deprotonate the alpha hydrogen.
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Perhaps I am wrong. Methoxy ion should be strong enough to pluck that alpha hydrogen.
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Perhaps I am wrong. Methoxy ion should be strong enough to pluck that alpha hydrogen.
I'd think so - having carried out work similar to that described in WO2007054254A1 in the past.