[amcavoy]

In the reaction give here:  http://www.chemistry.ohio-state.edu/cgi/organic/flashcard4?rseed=1194117145&topic=alkenes&type=card&card=16&aspect=answer I would like to find out why the addition of HBr seems to be anti-Markovnikov.  I would have thought that the Br^- would go to the more substituted carbon atom in the double bond.  Why doesn't this happen?

Thanks.

[ARGOS++]

Dear Amcavoy,

This addition of hydrogen bromide is contrary to hydrogen chloride and hydrogen iodide a “Free Radical Addition” and that follows the “Anti-“ Rule.

For more Information see under “Free Radical Addition" on:

"Markovnikov's Rule”

Good Luck!
                    ARGOS⁺⁺