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Topic: How can i do this?  (Read 4822 times)

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bugsmenot

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How can i do this?
« on: December 04, 2006, 06:12:44 PM »
8.180E21 atoms of Mn to milligrams?

i thought i do 8.180E21/6.02E23 * 54.94 * 1000. But apparently this isn't right. Any ideas?

Thanks

Offline Borek

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Re: How can i do this?
« Reply #1 on: December 04, 2006, 07:10:14 PM »
Convert to moles first. How many atoms per mole?
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bugsmenot

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Re: How can i do this?
« Reply #2 on: December 04, 2006, 07:31:42 PM »
The formula is KMnO4

bugsmenot

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Re: How can i do this?
« Reply #3 on: December 04, 2006, 11:10:45 PM »
*Ignore me, I am impatient*

Offline Yggdrasil

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Re: How can i do this?
« Reply #4 on: December 05, 2006, 12:44:34 AM »
Your procedure looks right to me.  What was the original question?

Offline Borek

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Re: How can i do this?
« Reply #5 on: December 05, 2006, 05:15:39 AM »
Your procedure looks right to me.  What was the original question?

Hm, I am quite sure there was no 6.02e23 in the formula, but it is now. I need a glasses - 8) - just not a dark ones.
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Offline Donaldson Tan

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Re: How can i do this?
« Reply #6 on: December 05, 2006, 05:40:22 AM »
But apparently this isn't right.

Who said your working is wrong? It is correct..

Number of Moles = (No. of Atoms / 6E23) mol
Molar Mass = 54.94 g/mol
1g = 1000 mg
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Offline DrCMS

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Re: How can i do this?
« Reply #7 on: December 05, 2006, 11:14:23 AM »
If the question is how many mg of Mn in 8.18x10^21 atoms of KMnO4 the calulation is

(8.18E21 * 54.93 * 1000) / 6.02E23 =74.6

the way you wrote can be misinterpreted

8.18E21 / 6.02E23* 54.93 * 1000 could be

(8.18E21 / 6.02E23)* 54.93 * 1000 = 74.6 as above

or

8.18E21 / (6.02E23* 54.93 * 1000) = 2.47E-7

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