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Question about Solubility Products
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Topic: Question about Solubility Products (Read 12447 times)
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Borek
Mr. pH
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Re: Question about Solubility Products
«
Reply #15 on:
December 06, 2006, 07:06:57 PM »
It is all in solution stoichiometry - imagine 1 mol of CaSO
4
was dissolved in some volume of water. How many moles of Ca
2+
and how many moles of SO
4
2-
are present in the solution?
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ChemBuddy
chemical calculators - stoichiometry, pH, concentration, buffer preparation,
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Jinn21
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Re: Question about Solubility Products
«
Reply #16 on:
December 06, 2006, 07:35:06 PM »
Well, the Molar mass of CaSO4 is 136g
Ca has a mass of 40g
and SO4 has 96g
So: Ca- 40g/136g = 0.29 mols -->0.30 mols
SO4- 96g/136g = 0.70 mols
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Borek
Mr. pH
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Re: Question about Solubility Products
«
Reply #17 on:
December 06, 2006, 07:58:44 PM »
No. Look at the reaction equation. And read second paragraph on this page:
http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations
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ChemBuddy
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