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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: dgolverk on September 13, 2008, 02:53:58 PM

Title: Arsenic Preciptation
Post by: dgolverk on September 13, 2008, 02:53:58 PM
Hi,
As part of my experiment I need to find a way to precipitate arsenic (arsenate ion AsO4-3) using:
i) Iron(iii) sulfate
ii) Calcium hydroxide
3Ca(OH) + 2AsO4 => Ca3(AsO4)2 + 3OH is that right?
What my equations will look like for case i) and ii)?
I already calculated the amount of arsenic in a liter of water (0.004mol/L), but I'm struggling with creating and equation that shows the reaction between the arsenate ion and the coagulants. I only need the equations, I will balance them myself.

Thank you very much,
Title: Re: Arsenic Preciptation
Post by: Borek on September 13, 2008, 03:43:53 PM
What is formula of arsenic acid?

Are you going to preciptate AsO43- from the solution of arsenic acid, or some salt, like Na3AsO4?
Title: Re: Arsenic Preciptation
Post by: dgolverk on September 13, 2008, 04:10:02 PM
I just need to precipitate arsenic in any form...
I just need to write a simple equation, something like that 3Ca(OH) + 2AsO4 => Ca3(AsO4)2 + 3OH, if that's right.
Title: Re: Arsenic Preciptation
Post by: Borek on September 13, 2008, 05:30:21 PM
Don't ignore charges in your equations, you are dealing with ions. What you wrote can be OK, once you will balance charge and add state of matter information.