pV = nRT , n =m/M
pV = mRT/M
M = mRT/pV
Rho = m/V
M = RhoRT/p
Given T = 360,15 K ,p = 150000 N/m2, spec. Gravity = 3.51 g/l
M = 3.51kg/m3 *8.314 Nm/molK*360.15 K/150000 N/m2 = 0,07 kg/mol = 70 g/ mol.
Formula C5H10 = 5 *12 + 10 * 1 = 70
n = m/M n= 3,51 g/70 g/mol = 0,05 mol in 1 l
4,51 *1023 Atoms divided by 15 = 3 *1022 molecules C5H10
This devided by 6.023*1023 gives also 0.05 mol