The L-(+)-lactic acid represents an optical (geometric) isomer of lactic acid. Just think of the equation as:
D-Glucose(aq) ::equil:: 2 Lactic acid(aq)
I'm not sure how I would factor that into the equation; ΔG°=-RTlnK.
That equation looks right to me - now how are you going to use it?
EDIT
XeLa
The L-(+)-lactic acid represents an optical (geometric) isomer of lactic acid. Just think of the equation as:
D-Glucose ::equil:: 2 Lactic acid
(the other information isn't involved in your calculations). That equation looks right to me - now how are you going to use it?
EDIT
XeLa
I was thinking this whole time 2L meant 2 liters. It's 2 L(+)? So my final equation would be (2*(-538.8 )-(-914.5)=-(8.314)(298)lnK and K=1.07. Spaces really would've been helpful in the original problem.