[orgo814]

Returning to chemistry and seemed to forget a lot of stuff... still struggling with making these solutions.

For example, one sample I need to make is 1650 ppm solution of albumin. I'm struggling with doing this. Mainly struggling with the mass of albumin to dissolve in whatever volume of water. Given that ppm is mg/L, if I decide on 10 mL.. 0.01 L then I need 6.06 x 10^-6 mg of albumin which is somewhat unrealistic. I'm just looking for any guidance on doing this realistically without having to use a huge volume

[hypervalent_iodine]

You will need to do some serial dilutions. This just involves making an initial solution of higher concentration with a workable mass of albumin, taking some volume of that and diluting it and repeating that process until you reach your desired concentration.

[orgo814]

that makes sense. thank you. what would be a good mass (concentration) to start out do you think?

[orgo814]

So, let's say I started with some concentration in some volume and then performed a dilution calculation M1V1=M2V2 to find the volume of what to take out. So, I take that out. How would I know how much to dilute it with?

[mjc123]

For example, one sample I need to make is 1650 ppm solution of albumin. I'm struggling with doing this. Mainly struggling with the mass of albumin to dissolve in whatever volume of water. Given that ppm is mg/L, if I decide on 10 mL.. 0.01 L then I need 6.06 x 10^-6 mg of albumin which is somewhat unrealistic.

Where do you get that figure? 1650 ppm is 1650 mg/L, so for 10 mL you need 16.5 mg - perfectly doable with care and accurate instruments. (Did you mean 6.06 x 10^-6 mol? or mol/L?)