Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: nozo on December 22, 2007, 07:50:09 PM
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Hi guys, can someone tell me if I did the ff. setup correctly?
How many grams of water are liberated by the complete decomposition of 100g of copper (II) sulfate pentahydrate?
CuSO4.5H2O ----> CuSO4 + 5H2O
100g CuSO4.5H2O (1 mol CuSO4.5H2O / 250g CuSO4.5H2O) (5 mol H2O / 1 mol CuSO4.5H2O) (90g H2O / 1 mol H2O)
Thanks!
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looks good
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The method is correct. Your molecular weight for water is incorrect though.
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Thanks guys ;D
Oh and yeah, 18g for H2O... lol
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lol yeah the molecular weight for water was wayyy off