Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Hemidol on November 06, 2009, 10:33:18 PM
-
Draw two equivalent resonance forms for nitric acid, HNO3. How many sigma bonds are there? How
many pi bonds?
The structures I imagine will look like...
O=N-O-H
||
O
with a net overall charge of 0... not sure where the charges on atoms would be.
I'm really confused about sigma and pi bonds...
-
You know how NO3- looks like? Add an H and you have yourself HNO3
-
Most simply, every single bond is a sigma bond. Each additional shared pair between two atoms is a pi bond.
-
The structure you imagined contains oxygen with 4 bonds which i think is not possible and also all Oxygens are attached to Nitrogen and no Peroxy bonds : )
NO3- is Resonance Hybridized [PM me for Structure : ) ] .. and it accepts a H+ and it may be added to any O- randomly .. Then you get the stricture Like ..
OH
/
O<--N=O 1. nitrogen is SP2 hybrdized,bonds in 120 with each other
2. SP2-P Sigma Coordinate Covalent Bond
3. SP2-P , one Sigma and one Pi
4. SP2-P , bond with O- which again bonded to h+
Browse for CO3-2 for similarity so that you can be more clear .. it accepts to 2H+ and forums H2CO3
Hope it Helped and i am correct : )
-
AH I see now. Thus this structure will have a total of 4 sigma bonds and 1 pi bond (as the double bond can indeed be considered sigma)--correct?
-
Yeah 4 Sigma and 1 pi bond : ) .. yea a double bond = 1 Sigma + 1 Pi . : )