Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Sis290025 on October 18, 2005, 05:24:37 PM
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A. Determine the total number of moles of solid sodium hydroxide required to react with 486.00mL of 0.8000M phosphoric acid (H3PO4).
Did I set up the equation correctly?
3NaOH + H3PO4 --> Na3PO4 + 3H20
Then, mol H3PO4(3mol NaOH/1mol H3PO4) = mol NaOH, where mol H3PO4 = (0.8000M)(0.486L)?
B. Determine the concentration of 232.7mL of lead nitrate, Pb(NO3)2 if the sample reacts exactly with 241.0mL of 0.391M potassium iodide (KI).
Equation: Pb(N03)2 + 2KI --> PbI2 + 2KNO3??
so mol PB(NO3)2 = 0.391 M KI *(.241 L KI) (1 mol Pb(NO3)2/ 2 mol KI)
Thanks. Please reply.
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Equations looks OK. Show final results and I will tell you if they are OK.
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a. 1.17 mol NaOH
b. 0.0471 M Pb(NO3)2
(from set-up)
Thanks.
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a. 1.17 mol NaOH
OK
b. 0.0471 M Pb(NO3)2
Wrong. You forgot one step of calculations.
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For B, that was the mol of Pb(NO3)2. :o
For M, 0.0471 mol Pb(NO3)2/ .2327 L Pb(NO3)2 = 0.202 M .
Must remember to read question! *ties bow to thumb* :-[
Thanks.
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Kim - look here:
http://www.chemicalforums.com/index.php?board=2;action=display;threadid=5381 (http://www.chemicalforums.com/index.php?board=2;action=display;threadid=5381)
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Who's Kim? ???
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Author of the moved post.