Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: connie_fhy on December 18, 2005, 08:00:10 AM
-
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fi16.photobucket.com%2Falbums%2Fb14%2Fsrx_srx%2Fchem.jpg&hash=f1afdbf4b019b23e52babdd49addb9628f1adb37)
is the reaction above correct???
I don't know where the -OH groups should be...
Would anyone kindly answer my question??
thank you very much~~
-
I'm not sure, but I think that if temperature is about 100C, then carbonyl may be oxidized into carboxyl to form 2 carboxylic acids. If temperature isn't high, then maybe simple hydroxylation takes place. But it seems to me that this product won't be stable. :-\
-
Oh~thank you for answering me~~ :D
but I asked some laboratory technical staff this afternoon~~
and I got a possible answer~~
-
I think that starting material is usually called dibenzylideneacetone.
-
connie_fhy, could you tell me whay is the answer? ???
-
hi
KMnO4 is a very strong oxidizing agent it hydrolyse your compound to two carboxilic acids rather than that you put.
this were correct if you were using Cr2O72- that is less oxidizing, you can undergo this oxidation by puting a temp. higher than that of of evaporationketone and higher than that of alcohol and use distilation method. thus isolating your product
but with KMnO4 no isolation of intermediate is possible you'll go directly to the final product carboxilic acid
-
You can sometimes isolate the diol product if you run the reaction at colder temperatures. This process is used on industrial scale for dihydroxylation!
-
well it is a new important information that i'll take in conisedration
i thought it couldn't happen with KMnO4
thank