Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Messi on October 13, 2012, 08:58:58 PM
-
If I have a solution of Sodium Acetate (CH3OH), what species would I expect in solution in order of decreasing concentration?
I said:
CH3COONa
H2O
CH3COOH
NaOH
H+ & OH-
I wasn't sure where I would put Na+ and CH3COO- as I guess some of these ions would be expected in the solution, no?
-
I have a solution of Sodium Acetate (CH3OH)
A methanolic solution of sodium acetate? Can you explain how you propose to form water from sodium acetate and methanol?
-
Sorry, I meant Sodium Acetate (CH3COONa)! I had a brain fart when I wrote the molecular formula!
-
I wasn't sure where I would put Na+ and CH3COO- as I guess some of these ions would be expected in the solution, no?
Sure, can you work on the rest? How much [NaAcetate] molecular do you expect to exist an aqueous solution?
-
Ok I guess I'll put this as my list in order of decreasing concentration:
I said:
CH3COONa
H2O
CH3COO- & Na+
CH3COOH
NaOH
H+ & OH-
I think the above list is correct? It makes sense to me in a conceptual manner.
-
Acetic acid is a weak one, so you should expect quite strong hydrolysis.
-
So you expect sodium acetate to exist in solution mostly as a molecular species? So, comparing a solution of sodium acetate in water, you think the properties are more like sucrose in water, and less like sodium chloride in water? That is to say, sodium acetate isn't very ionic in character? A solution won't conduct electricity, for example?
-
Why would you expect less water than sodium acetate? What is the solubility of sodium acetate in water?
-
Well here is my rational:
There are two equilibriums going on... one of them is:
H2O :rarrow: OH + H
The other one is:
CH3COONa + H20 :rarrow: CH3COOH + NaOH
H2O rarely breaks down into OH and H so these should be in the lowest concentration. NaOH is a strong base so dissociates almost completely so there should not be much NaOH left. If NaOH reacts with CH3COOH then there should not be much CH3COOH either?
So my list is:
CH3COONa
H2O
CH3COO- & Na+
CH3COOH
NaOH
H+ & OH-
-
You can safely assume acetate is dissociated 100%. You can also assume there is almost no NaOH in the solution, as a strong base it is 100% dissociated as well.
You are still missing the hydrolysis part which is what the question is most likely about.
-
Hydrolysis part? Didn't I show the Sodium acetate being hydrolysed into NaOH and acetic acid?
-
You listed them, but you ignored other hydrolysis products.
-
Do you mean... H2O + H2O :rarrow: H3O + OH ?
-
No.
Write reaction equation of the CH3COO- hydrolysis. What are the products?
-
Did I not already write them? ???
CH3COONa + H20 :rarrow: CH3COOH + NaOH
or
CH3COO + H20 :rarrow: CH3COOH + OH
-
what species would I expect in solution in order of decreasing concentration?
In water solution of sodium acetate you have a few moles of sodium acetate in 1 liter and ~50 moles of water.
-
what species would I expect in solution in order of decreasing concentration?
In water solution of sodium acetate you have a few moles of sodium acetate in 1 liter and ~50 moles of water.
Ok, yes, I agree with that. So to reformat my table, I would put:
H2O
CH3COONa
CH3COO- & Na+
CH3COOH
NaOH
H+ & OH-
-
CH3COO + H20 :rarrow: CH3COOH + OH
Stop omitting charges.
If there is an OH- produced per each CH3COOH produced, is it possible that the concentration of OH- is much lower than the concentration of CH3COOH?
-
Good point Borek. Sorry for omitting charges.
I guess my final table in order of decreasing concentrations should read:
H2O
CH3COONa
CH3COO- & Na+
H+ & OH- & NaOH & CH3COOH
I am not sure if there would be the same amount concentrations of CH3COONa and CH3COO- & Na+.
-
You were told more than once that CH3COONa is dissociated 100%, yet you still list it as the second most important species.
-
My apologies.
H2O
CH3COO- & Na+
H+ & OH- & NaOH & CH3COOH
Seems correct I guess.
Thank you for correcting me Borek. As you can tell, I am not very brilliant.
-
My apologies.
H2O
CH3COO- & Na+
H+ & OH- & NaOH & CH3COOH
Seems correct I guess.
Thank you for correcting me Borek. As you can tell, I am not very brilliant.
After thinking for a long time, I would probably change my answer to:
H2O
CH3COO- & Na+
OH-
CH3COOH
H+
What do you guys think?
-
Much better.
-
Much better.
Is "much better" 100% correct? :)
-
Exact answer depends on how much you are expected to know and what level of details you were already taught. At some level this is a 100% correct answer, at other levels it is incomplete.
-
And at some levels it's wrong! ;)