Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: huma on January 31, 2006, 05:51:39 PM
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ok i got the first part can u help me iwth the second part?
4NH3 + 7O2 --> 4NO2 + 6H2O
a. How many grams of oxygen are necessary to produce 4.50 moles of NO2?
so i got.... 252 grams of O2
i did :
7 moles O2 produce 4 moles of NO2
x moles O2 produce 4.5 moles of NO2
x= 7 * 4.5 / 4 = 7.875 moles
m= n * MM = 7.875 * 32 = 252 grams of O2
now they ask.
b. How many molecules of water are produced when 2.25 moles of ammonia are completely reacted?
???
help
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How many molecules of water are produced when 2.25 moles of ammonia are completely reacted?
Calculate moles - you should know how many particles are in one mol. That's just the mole definition btw.
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ok let me get back to u on that..
first let me do the problem
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Calculate moles - you should know how many particles are in one mol. That's just the mole definition btw.
ok let me get back to u on that..
first let me do the problem
BOREK is right. get the mole first of water produced when 2.25 mol of ammonia completely reacted and then multiply that to value of Avogadro's number.