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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Makaveli on June 18, 2013, 09:08:06 AM

Title: Chemistry, calculating mass, mol and element mass?
Post by: Makaveli on June 18, 2013, 09:08:06 AM

Lets say i have this reaction:

CH₃OH + O₂ => CO₂ + H₂O

I start by balancing it to:

2CH₃OH + 3O₂ => 2CO₂ + 4H₂O

If we asume that i have 0,500g 2CH₃OH, we can find this:

2CH3OH - n -> (0,01561) | M -> (32,023) | m -> 0,500

3O2 - M -> 31,998

2CO2 - M -> 28,011

4H2O - M -> 18,015

Now, i need to find n or m for the rest of the compounds, and i cant do that with just M, i need m or n, how do i find one more property to calculate the rest of the table?

Title: Re: Chemistry, calculating mass, mol and element mass?
Post by: Borek on June 18, 2013, 09:36:39 AM

You already listed m and n for methanol. Do you know how to read the reaction equation?

http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations

Title: Re: Chemistry, calculating mass, mol and element mass?
Post by: Makaveli on June 18, 2013, 09:42:42 AM

Well yes, i have the relation, but do i just use the relation to get n for the others?

If
2CH3OH - n -> (0,01561)

Then
4H2O - n -> (0,03122) ??

Title: Re: Chemistry, calculating mass, mol and element mass?
Post by: Borek on June 18, 2013, 10:03:37 AM

Yes. That's what the stoichiometry is about.