Chemical Forums
Specialty Chemistry Forums => Citizen Chemist => Topic started by: nilocg on April 04, 2016, 02:59:34 PM
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Im not sure if this is the correct place to post this so please move in necessary.
I am trying to make a 5000ppm N solution using urea(46-0-0), i would love for someone to proof my math here, I am getting a different value when using online calculators.
So here is my math, please correct me:
1gram urea into 1 liter of water will provide 460ppm(mg/l) N
5000ppm/460ppm= 10.87g Urea
So 10.87g urea into 1 liter will add 5000ppm Nitrogen.
Is this correct?
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Looks OK to me.