Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: ryans122 on October 19, 2017, 01:41:28 AM
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I'm an IB chemistry SL student doing an IA on the vitamin C concentration of orange juice. We haven't learned about the titration process, so here is what I have done so far:
5KI + KIO3 + 3H2SO4 -> 3I2+ 3K2SO4 + 3H2O
This is the equation for producing the iodine solution. Now using a titration process, I added the iodine solution to the orange juice. I measured the volume of Iodine solution used.
Here is the formula for the reaction between the vitamin C and the Iodine solution.
C6H8O6 + I3- + H2O → C6H6O6 + 3I- + 2H+
I'm not sure where the Triiodide comes from. In the Iodine solution, we have Iodine, but the next reaction requires triiodide. Can someone explain this to me? I'm not a very good chemistry student.
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Just googling for triiodide should quickly lead you to an answer.
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Just googling for triiodide should quickly lead you to an answer.
I have, but I've gotten something along the lines of the Iodine being more soluble. I don't understand how the Iodine somehow changed to the triiodide.
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I have, but I've gotten something along the lines of the Iodine being more soluble.
Increased solubility is a final effect, yes.
I don't understand how the Iodine somehow changed to the triiodide.
Have you read the wikipedia article on triiodide? It contains reaction equation that explains what is going on.