Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: jakel580 on April 24, 2019, 11:01:53 PM
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The IR spec clearly shows a carbonyl is present, which means an oxygen is present.
The mass spec data shows there is an M+ peak of 142, with no Cl/Br present.
From this data, I'm gathering a formula of C10 H6 O. (10 X 12 + 6 + 16 =142) This leads to a degree of unsaturation of 8, which seems fairly high. I feel as if I'm missing something here and any help would be greatly appreciated, thanks!
Edit: Forgot about integral scaling in the hnmr, which will change the number of protons. Thanks anyway!
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Wouldn't C9H18O make a lot more sense? Unsaturation of 1, which is the carbonyl
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N-butanol is close but not exact
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@OP,
Do you see indications of unsaturated carbons in the 1H spectrum?
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More like, do you see any unsaturated carbons in the FTIR! I don't. OP where would these show up normally?
This is a pretty simple molecule OP, you can do it!