Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: AussieKenDoll on July 16, 2019, 10:18:36 AM
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Why Nucleophilic substitution of pyridine undergoes predominantly at C2 and C4 but not on C3, why?
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Draw the mechanism, including all resonance structures for the anionic intermediate. Then, think about them. Where is negative charge more stable in anions? That will explain it.
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the positive charge is on C2, C4 and C6 on the resonance structures? but I still do not understand why