Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Joshua Law on August 20, 2019, 08:23:46 AM
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Hello there!
Can anyone please tell me how to theoretically synthetize 1-cyclopentylpropan-1-amine from cyclopentene in exactly 6 steps (no more, no less steps)?
Thank you for all your answers!
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Do you have any suggestion? Is it possible to add something to the double-bond as a starting-point?
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I find that it is generally easier to work backwards from the product than the other way around. Please show us what you have tried so far.
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I started with Friedel-Crafts reaction using propanoyl chloride and AlCl3, with cyclopentylpropane-1-one as a product of the first step. Then I thought about reduction of the ketone using NaBH4 and MeOH resulting into 1-cyclopentylpropane-1-ol (that's the second step). As the third step using TsCl and pyridine to create (1-chloropropyl)cyclopentane.
The problem is that everything that comes to my mind uses only 5 steps, not 6 I need. :-\
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I draw the cuprate wrong, sorry!
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That's perfect, thank you! ;)
To be honest, this way of solution really didn't come to my mind at all ;D
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The reason I love this site so much is that intelligent chemists who know the answers already makes the OP think before just answering it (Which is also a part of the site rules), this site has very smart chemists that we are fortunate to have to help us and pass the wisdom