Chemical Forums
Specialty Chemistry Forums => Chemical Engineering Forum => Topic started by: Enthalpy on November 09, 2019, 04:23:21 PM
-
Hello dear friends!
The chemical separation of rare earth metals is difficult and costs more than the extraction of the ore. So could distillation separate rare earth metals? (Of course I didn't check if it's already done).
Most 1kPa boiling points spread nicely. Exceptions are 66K for Tb/Pr (or 2.6%, comparable with 100°C and 110°C), 18K for Ce/La, 2K for Pr/Gd. For those pairs, the 1atm boiling points or the melting points spread, so a later step might separate them, distillation at a different pressure or a chemical process.
1kPa 1atm mp Element
K K K
==============================================
1047 1465 1097 70 Yb ytterbium
1234 1796 1099 63 Eu europium
1421 2061 1345 62 Sm samarium
1570 2217 1818 69 Tm thulium
1954 2831 1680 66 Dy dysprosium
2040 2964 1734 67 Ho holmium
2163 3132 1802 68 Er erbium
2296 3336 1297 60 Nd neodymium
2505 3491 1629 65 Tb terbium
2571 3779 1208 59 Pr praseodymium
2573 3535 1585 64 Gd gadolinium
2653 3663 1925 71 Lu lutetium
2754 3705 1068 58 Ce cerium
2772 3726 1193 57 La lanthanum
==============================================
The distillation tower's material is badly difficult. The best refractory metals have a very low vapour pressure at such temperature (notice the 1kPa, 1Pa and 13mPa), but I suppose they dissolve in the molten mischmetal to pollute the most refractory rare earth outlet and fail mechanically.
1Pa mp Element
K K
==============================================
2639 2128 40 Zr zirconium
2689 2506 72 Hf hafnium
2742 2896 42 Mo molybdenum
2942 2750 41 Nb niobium
3297 3290 73 Ta tantalum
3303 3459 75 Re rhenium
3477 3695 74 W tungsten
==============================================
Would plain ceramic, or a ceramic coating, resist molten mischmetal better? For the following oxides, I'd say no. I've taken only oxides of refractive metals because of MgO's bad example: liquid Al corrodes it as metallic Mg is volatile. The heat of formation per mole of oxygen atoms is -409 to -635kJ/mol while rare earth metals have -568 (Eu3O4) to -633 (Er2O3). I haven't checked the carbides nor borides. Graphite?
13mPa dHf/O mp Compound
K kJ/mol K
==============================================
2200 -409 2145 Ta2O5
2300 -635 2683 Y2O3
-380 Nb2O5
2500 -550 2973 ZrO2
2800 -572 3031 HfO2
==============================================
-568 Eu3O4
-633 Er2O3
==============================================
So maybe uncoated C, Ta, Re, W can make the tower to distill the more volatile rare earth metals, which might be useful.
Marc Schaefer, aka Enthalpy
-
I have heard of at least a few metal azeotropes. I'm afraid that metals with such similar properties will also create them.
-
Hi AWK, thanks for your interest!
Azeotropes, yes... I have no data about metal azeotropes.
My guess is that distillation won't be the magic process that separates each individual lanthanide ultrapure in one step. If a pair of columns with varied pressures can separate half of the lanthanides and the other half demands a separate process, it could be worth it.
-
The more refactive lanthanides would distill under lower pressure to spare the column's materials. Beginning here with terbium, all data from Wiki:
10Pa 100Pa 1kPa mp Element
K K K K
===================================================
1979 2201 2505 1629 65 Tb terbium
1973 2227 2571 1208 59 Pr praseodymium
2028 2267 2573 1585 64 Gd gadolinium
2103 2346 2653 1925 71 Lu lutetium
2194 2442 2754 1068 58 Ce cerium
2208 2458 2772 1193 57 La lanthanum
===================================================
Tb and Pr spread more at 1kPa, Pr and Gd spread less badly at 10Pa and 100Pa, Ce and La remain close. The process speed must be a limit.
Marc Schaefer, aka Enthalpy
-
Ramblings about the solubility of metals in melts.
Ag and Au dissolve in molten Sn63Pb37 but Cu doesn't.
- The difficulty to separate atoms from the solid metal, represented by the vapour pressure, is one factor.
- The temperature for 1kPa is 1782K for Ag, 2281K for Au, 2089K for Cu, so there are other factors.
- The strength with which the melt incorporates foreign metal atoms is the other factor.
- Cu, Ag and Au have similar valences, so this isn't the reason.
- But the molar volumes can explain these metal solubilities. Nothing revolutionary to metallurgy.
cm3
=========
Cu 7.11
Ag 10.27
Au 10.21
=========
Sn 16.29
Pb 18.26
=========
Sn and Pb being much bulkier, they dissolve Ag and Au a bit, and the smaller Cu less.
So to build a distillation tower, what metal would not dissolve in molten mischmetal?
Refractory metals are small and lanthanides rather big:
cm3
=========
Re 8.86
W 9.47
Ta 10.85
=========
Er 18.46
...
La 22.39
Yb 24.84
Eu 28.97
=========
This gives some hope that they dissolve little (or slowly). If following that stretched logic, W would dissolve less than Ta, and expensive Re even less.
Marc Schaefer, aka Enthalpy
-
Eu, Yb, La have a molar volume distinctly bigger than the other lanthanides. Could this serve to scoop them from the mischmetal?
cm3
=========
Sr 33.94
Ba 38.16
K 45.94
=========
Er 18.46
...
Ce 20.69
La 22.39
Yb 24.84
Eu 28.97
=========
Ligands make complexes selectively with preferred ion sizes. I bet this is already done for lanthanides.
Alternately, I suggest the selective dissolution of Eu, then Yb, later La, in a molten metal, if there is such a selectivity. Still stretching the previous logic, the solvent would be a metal with huge molar volume: Sr, Ba, K and few others, at a temperature where lanthanides are little soluble. Then, Eu would dissolve preferentially from mischmetal powder. With more heat, Yb would be scooped, and even more heat would extract La.
Extraction could evaporate the solvent. Moving the mischmetal and the solvent in opposite directions would extract much of the target element but evaporate only well loaded solvent.
Maybe. And playing with matches, the big way.
Marc Schaefer, aka Enthalpy
-
Even if I completely botched the explanation based on molar volumes, but some melt achieves to dissolve selectively some of the lanthanides from mischmetal powder, I'll be happy of course.
-
https://www.ameslab.gov/mpc/the-ames-process-rare-earth-metals
-
Thanks AWK!
So distillation or sublimation serve already for crude separation.
A bad news in the pptx there on page 44 is that Sc at its 1814K melting point dissolves 3.2at% Ta from the crucible. Unclear if that's a solubility or if time limits the amount, but such a proportion isn't acceptable for a distillation column. At Ames, they remove the dissolved amount of crucible by distillation or by solidification. Rebuilding a Ta crucible regularly can't make the process cheaper.
Hopefully W can operate at the same 1800K but dissolve little: it accepts 184K more than Ta for 1kPa vapour pressure and melts at 405K higher. W atoms also mismatch lanthanides size more than Ta do.
At 1kPa, 1800K distillation limit to Yb, Eu, Sm, Tm. If accepting 100Pa, Dy and Ho would fit. That's not brilliant. At least, these elements spread by >100K.
I have creep data about refractory metals and alloys and could check how weak they are at 1800K. Unless I find a solubility of C in hot lanthanides, because otherwise graphite would perform decently in 1800K reducing condition.
Levitation melting and jet levitation allow higher temperature but won't replace a distillation column
https://www.chemicalforums.com/index.php?topic=69134.msg357926#msg357926
https://www.chemicalforums.com/index.php?topic=69134.msg357960#msg357960
-
The effect of atom size matching between metal solute and solvent is long known. One example there (I access only the abstract)
https://www.sciencedirect.com/science/article/abs/pii/0022508866900890
They measured the solubility of Ta and W in lanthanides at varied temperatures, and:
"The solubility of [small] Ta and W vary inversely with the atom size of the lanthanide solvent."
"W is a much better crucible material for the lanthanides than Ta"
There too I access only the abstract:
https://aip.scitation.org/doi/abs/10.1063/1.4962595
"Mol/mol solubility of W in Ce is 2ppm at 800°C, increasing to 240ppm at 1540°C."
There on page 25:
https://www.ameslab.gov/files/REM_presentation_ShortForm.pptx
"Sm, Eu, Yb and Tm can be melted in Ta crucible without contamination" (1815K for Tm)
Also, they use metallic Ca to reduce R from RCl3, and later Ca is evaporated away from R.
This gives me hope that, as I suggested previously
- Some refractory materials let a distillation apparatus separate the most volatile lanthanides.
- Liquid Ca or other can selectively dissolve the biggest (smallest too?) lanthanides and be later evaporated away.
-
https://www.hindawi.com/journals/stni/2019/4121285/
-
Thanks AWK!
Meanwhile I've read (yes!) that the rare earth oxides are separated prior to reduction (at least it's how I understood). This uses possibly liquid/liquid separation, possibly chromatography, and apparently the main process use ion exchange resin. Though, stone-old documents
https://lib.dr.iastate.edu/cgi/viewcontent.cgi?article=13731&context=rtd
https://patentimages.storage.googleapis.com/f8/fe/d4/a44f518ca41c96/US2897050.pdf
https://patentimages.storage.googleapis.com/b4/9f/a0/0c451a55fb45ff/US3228750.pdf
suggest that this step takes bulky hardware for a small throughput, is slow, and needs iterations.
So how convenient does ion exchange look like? Somebody willing to risk a gut feeling here?
If ion exchange is easy, quick, cheap for lanthanides, thinking at distillation is useless.
-
Some rare earth metals have a distinctly smaller molar volume, especially Sc obtained from the same ore, and a few more. Sc is reportedly difficult to separate. Would a metallic melt of small molar volume dissolve selectively these elements? Or the most easily molten or evaporated target elements, combined with the molar volume.
I've listed some small solvent metals, volatile to separate from Sc, Er, Ho. Some add drawbacks to the general explosion risk, Ag seems less dangerous. Alloyed solvents make eutectics.
cm3
=========
Mn 7.35
Zn 9.16
Ag 10.27
Ga 11.80
Li 13.02
Mg 14.00
Hg 14.09
=========
Sc 15.00
Er 18.46
Ho 18.74
Dy 19.01
Tm 19.13
Tb 19.30
Sm 19.98
Y 19.88
Gd 19.90
...
Eu 28.97
=========
Marc Schaefer, aka Enthalpy