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Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Artem_111 on November 16, 2019, 12:00:46 PM

Title: Potassium peroxydicarbonate
Post by: Artem_111 on November 16, 2019, 12:00:46 PM
Is it possible to obtain Potassium peroxydicarbonate by passing CO2 through KO2 at 0 ° C in absolute ethanol? What equation describes this process?
Title: Re: Potassium peroxydicarbonate
Post by: chenbeier on November 16, 2019, 02:58:12 PM
In my knowledge it can only obtained by electrolysis.

https://en.m.wikipedia.org/wiki/Peroxydicarbonate
Title: Re: Potassium peroxydicarbonate
Post by: AWK on November 16, 2019, 06:04:58 PM
Is it possible to obtain Potassium peroxydicarbonate by passing CO2 through KO2 at 0 ° C in absolute ethanol? What equation describes this process?
Ethanol is a solvent for this reaction. The reaction itself is very simple. Just try.
Title: Re: Potassium peroxydicarbonate
Post by: Artem_111 on November 17, 2019, 10:17:44 AM
In the interaction of 71 g of potassium peroxide with carbon dioxide at 0 degree C in absolute ethanol, a white substance powder was obtained in 80% yield. What is an amount of solid residue (in g) which can occur after complete decomposition of the substance by heating.
Title: Re: Potassium peroxydicarbonate
Post by: AWK on November 17, 2019, 10:23:30 AM
Start from a balanced reaction.
Title: Re: Potassium peroxydicarbonate
Post by: Artem_111 on November 17, 2019, 12:03:05 PM
Start from a balanced reaction.
reaction KO2 + CO2 = K2CO3 + O2 does not fit the condition, and KO2 + CO2 = K2C2O6 is not equalized because there is no deoxidant
Title: Re: Potassium peroxydicarbonate
Post by: chenbeier on November 17, 2019, 12:29:15 PM
Nothing is balanced in your equations? Do this first. KO2 is potassiumhyperoxide.
Title: Re: Potassium peroxydicarbonate
Post by: Enthalpy on November 18, 2019, 12:54:07 PM
The reaction itself is very simple. Just try.
Simple, but explosive? Superoxide and fuel.
Title: Re: Potassium peroxydicarbonate
Post by: AWK on November 18, 2019, 02:46:11 PM
Quote
What equation describes this process?

So far we are talking about writing and balancing reactions.