Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: bfl27 on January 16, 2020, 12:00:09 PM
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Hi,
I was hoping someone could clear up some confusion I'm having regarding balance a reaction at the concentration of the Lower Flammability limit of Pentane Fuel reacting in Air (assuming 79% N2 and 21% O2).
I'm confused on the meaning of 1.5% volume pentane in air. I attached an image of two ways, and can't figure out which is correct.
Thanks for any help.
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so your question is essentially...
does 1.5% by volume pentane mean
1.5L pentane / 100 liters air
or
1.5L pentane / 100 liters total vapor = 1.5L pentane / (100 L pentane + N2 + O2 combined)
it's the later of the two.
1.5% pentane = 1.5L pentane + 98.5L air