Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: keerthana on February 11, 2020, 01:02:16 PM
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Hi everyone. My question may look so simple but I wish to clear my doubt on some basics. I am preparing a reaction for producing polymer, sodium polyacrylate. For this,
1) 1M Acrylic acid CH2CHCOOH solution is prepared of 300 mL.
2) 1M NaOH solution is prepared of 300 mL.
3) Both were mixed to obtain pH=7. The reaction is as follows:
CH2CHCOOH + NaOH = CH2CHCOO-Na+. This may not be actual reaction, since dissociation of weak acid also matters.
Here, it is weak acid and strong base mixed at neutral pH. The acid will be in both dissociated and undissociated form. Now How do I calculate the sodium acrylate salt formed?
Though it looks simple, I am not satisfied in its calculation. Kindly do help.
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The amount of NaOH will convert the whole acid to the salt.First the dissoziated form will be neutralized, but new dissoziated acid over the eqilibrium will be formed until everything is neutralized.
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So, at neutral pH, whether the following reaction can completely take place?
CH2CHCOOH + NaOH = CH2CHCOONa + H2O
If this is the case, what is the amount of salt formed? can you explain in detail with calculations?
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Can I ask why you are doing the reaction so dilute and why you are neutralising the acrylic before polymerisation rather than after?
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The procedure I referred to a paper in literature. Actually what I need to know is what will be the amount of salt formed?