Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: bluebunny2020 on February 24, 2020, 11:11:06 PM
-
Anyone know the mechanism for this process? I've looked all over the internet but haven't found anything on how NaBH4 actually removes Hg-OAc
Thanks ahead of time!
-
The mechanism I have seen has these steps:
Hydride ion (H-) from borohydride displaces the acetate on mercury to form R-Hg-H
Homolytic cleavage of R-Hg bond.
Transfer of H radical to carbon radical from Hg-H to form R-H bond (C-H) and free mercury metal.
This was established by Whitesides back in 1970.
https://pubs.acs.org/doi/pdf/10.1021/ja00725a039
-
Pasto and Gontarz published a similar study on the reduction of -Hg(OAc) with borohydride a year before Whitesides. Same mechanism as the one described above.
JACS 1969, 91(3), 719-721
https://pubs.acs.org/doi/pdf/10.1021/ja01031a036