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Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: ego8eimi on September 07, 2006, 06:46:46 PM

Title: Orbital Hybridization
Post by: ego8eimi on September 07, 2006, 06:46:46 PM

Hello,
In class we went over this question:
If a carbon forms on sp6 orbital (i.e. 1/7s and 6/7p just as sp3 is 1/4s and 3/4p) what is the hybridization of the other three equivalent orbitals?

While answering the question a student went up and started doing some sort of equation that involved fractions. The student subtracted 7/7 s and 21/7p from 1/7s and 6/7p getting 6/7s and 15/7p which came to an answer of 2/7s and 5/7p or s2p5.

My question is how did they get these numbers? I tried asking but they moved on (and this was office hour). I want to fully understand what it is exactly that they are doing here.
Thank you
Erica

Title: Re: Orbital Hybridization
Post by: bluemonster on October 05, 2006, 09:15:52 AM

what !!!  :o

Quote

If a carbon forms on sp6 orbital (i.e. 1/7s and 6/7p just as sp3 is 1/4s and 3/4p) what is the hybridization of the other three equivalent orbitals?

I don't know about this hybridization of carbon !  :-[  As I know, A carbon have three the hybride states, not more !  ::)
You can give a example of the case in which the carbon form on sp6 orbital ?
thanks a lot !!   ;)

Title: Re: Orbital Hybridization
Post by: english on October 05, 2006, 11:27:28 AM

sp⁶?  I thought it only went as far as sp³d².

Never heard of sp⁶ carbon.  There is only sp, sp², and sp³.

There's only 3 p orbitals to mix!