Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Darkstar on September 08, 2004, 11:02:58 PM
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Can you oxidize cyclopentene into 1,5-pentadiol in one stage?
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Ozonolysis with a reductive work-up (NaBH4) should do the trick.
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Yes, apparently this is what they mean. A one stage process that consists of two parts :) I just thought maybe there's some sort of magic reagent I've never heard about, some selenium astatide or something...
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I don't know much selenium chemistry, so there might be something.
Ozonolysis is always a two stage process. I think that the NaBH4 step is essentially just tossing in some NaBH4 when the ozone addition is done, so it's virtually a one step conversion. The ozonolysis to give the aldehydes would use a Me2S workup, so it's not like you would avoid a step otherwise.
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with H2O2
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H2O2 will not split up the cyclopentene molecule at the C=C bond (?). It will only lead to epoxidation.
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How about Jone's Reagent? Or Using Cold Alkali KMnO4 ??
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I don't think that Jones reagent will oxidize double bonds. KMnO4 can dihydroxylate (sometimes even cleave to the aldehydes, but then will oxidize to the acid), but then you still have to do another step or two to open the ring and get the alcohols.
BTW, H2O2 is a poor epoxidizing agent for olefins. It does, however, work well for epoxidizing enones. For olefins, electrophilic epoxidizing agents are better (e.g. m-chloroperbenzoic acid).