Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Fish200398 on March 22, 2020, 07:22:19 AM
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Using 2.5 Amperes, pt electrode , and 112 ml gas generated.
How many charges flow?
Cl2 gas generated in anode
Cu (s) formed in chatode
Can i assume 112 ml at STP ?
112 ml Cl2 means 0.05 moles of Cl2 means involved 0.05 F electrons.
1 F requires 96500 charges
Means 0.05 F requires 4.825 C
Is it true?
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Using 2.5 Amperes, pt electrode , and 112 ml gas generated.
How many charges flow?
Cl2 gas generated in anode
Cu (s) formed in chatode
Can i assume 112 ml at STP ?
If no other information is given that's better than nothing.
112 ml Cl2 means 0.05 moles of Cl2 means involved 0.05 F electrons.
No. You are on a right track, but you made two errors. One is just a simple math, the other is related to the reaction equation.
1 F requires 96500 charges
Not "charges", coulombs. Just like you don't say water boils at 100 temperatures nor Moon is 384 thousands distances from Earth. Coulomb is a charge unit just like kilometer is a distance/length unit, and degree (be it Celsius, or Fahrenheit) or Kelvin are units of temperature.
Means 0.05 F requires 4.825 C
Is it true?
You not only managed to propagate all previous mistakes in your calculations (that would be understandable) but you again failed at math.
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2Cl- = Cl2 + 2e
0.005 moles gas Cl2, means 0.005 F electrons
Means 482.5 C flows through the electrolysis
Is it true?
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Mol ist not the same like Farad.
Q = n* z* F
Charge = mol* amount of electron in reaction * Faraday constant.
Fill in with your values.
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I just realized the mistake is Cl2 and electrons has coefficient of 1:2
So there are 0.01 F.
Btw, its true right that Cl2 was formed in anode?
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What is 0,01 F?
You have 112 ml = 0,112 l Cl2
How much mol is it?
This has to be multiplited with die amount of transferred electrons and the Faraday constant.
Die Value will be in Coulomb.
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At STP 1 mol gas = 22.4 L
0.112 L = 0.005 moles Cl2
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Correct, then you can calculate the charge in Coulomb.