Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Timeless Thinker on April 28, 2020, 07:17:42 PM
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Aluminum is a soft, silvery-white metal used in a variety of items, from window frames and kitchen utensils to aircraft. Aluminum must be processed via Al2O3(s) from Bauxite. Our bauxite source claims their product contains about 65 % Al2O3(s) by mass. The equation for electrochemical production of aluminum is
2 Al2O3(aq) + 3 C(s) ⟶ 4 Al(l) + 3 CO2(g)
(a) How much bauxite is required to produce 2.0 million metric tons of aluminum metal per year by electrolysis? (a metric ton is 1000 kg)
(b) Estimate the energy amount needed to produce this amount of aluminum in 1 year if the operating voltage for a typical aluminum generating cell is 6.0 V.
What formulas do I use for these questions? Where does voltage come into play in part b?
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How is electrical energy described. Which unit does it has?
You need current calculated by law of Faraday from a. and the voltage.
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But How do I find amps for part a? There seem to be two variables there.
The equation I have so far is:
Amps x Seconds/year x 1C/Amp·Second x 1/96485C x 4 mol Al/12 mol e- x 203.92 g of 2Al2O3
But should I use 2(Al2O3) as molar mass or should I just use 101.96?
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What is the formula for faraday law?
Which variables do you have?
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But How do I find amps for part a? There seem to be two variables there.
No, this is just a simple stoichiometry, one that even doesn't require balanced reaction equation. All you have to do is to follow aluminum.
If you have 1 kg of bauxite, what mass of Al2O3 does it contain? And how much Al?
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The equation for electrochemical production of aluminum is
2 Al2O3(aq) + 3 C(s) ⟶ 4 Al(l) + 3 CO2(g)
WHAT??
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This can be used, because the Carbon rods will be oxidiesed as anodes by the oxide ions
The cathion reaction is the reduction of aluminium ions. The anode reaction is the oxidation of carbon.
Combination of both gives a normal redox reaction. Even current is used for an electrolysis.
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1kg of bauxite has .650 kg of Al2O3 and that has .344 kg of Al.
Do I just set up a proportion of .344/1kg = 2 million tonnes/ x tonnes?
So then the answer is 5.812 million metric tonnes?
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1kg of bauxite has .650 kg of Al2O3 and that has .344 kg of Al.
Do I just set up a proportion of .344/1kg = 2 million tonnes/ x tonnes?
So then the answer is 5.812 million metric tonnes?
Yes
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And part b, where does the voltage come into to equation? How do I use that to solve for amps?
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Do you know Faraday Law ?
How do you calculate Power and Energy .
The inventer of the steam engines name multiplied by time.
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Yes: Joules = Voltage x Current x Time
But I'm not sure if my equation to solve for Amps is correct. This is what I have so far:
grams Al x (1 mol Al/101.96g) x (A·S)/C x 96486C/1 mol e- x 12 mol e-/4 mol Al = seconds/yr
Should I use 1 mol Al/101.96g? In the reaction, there is a coefficient before the 2Al2O3. Also, is my mols of e-/mols of Al correct?
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The Faraday law is given m = I* t * M/(z*96485 As)
m = mass [g], I = current [A], t = time [s ], z = amount of electron for Al it is 3, M = molar mass [g/mol]
Solve for I.
The reaction is Al3+ + 3 e- => Al
So no need for coefficients.
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That makes much more sense, thank you. Should my final answer then be in Amps?
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Your final answer should be in something like watt hour or joule.
After getting the amps you have to calculate the energy.
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So it should be J= Amps x Volts x Seconds,
And the seconds should again be seconds/year?
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Yes correct.
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This [reaction] can be used, because the Carbon rods will be oxidiesed as anodes by the oxide ions [...]
Danke chenbeier!