Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: baffled9001 on May 23, 2020, 02:50:32 AM
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Hi everyone, I got stuck on a homework problem and was hoping for some help.
It's "explain why this experimental procedure is incorrect: 'To make 1.00 L of a 1.00 M NaCl solution, I will dissolve 58.5 g of NaCl in 1.00 L of water.' "
But 1 L solution * 1 mol NaCl/1 L solution * 58.44 g NaCl/1 mol NaCl = 58.44 g NaCl. So wouldn't dissolving 58.44 g NaCl in 1 L H2O result in a 1 M NaCl solution, after all? I'm not seeing how it doesn't.
So then I thought the problem might have more to do with experimental procedure than with calculations. But when I tried looking up "how to prepare a 1 M solution of NaCl" on YouTube, the two people I watched did exactly that. They poured most of 1 L of water into a container, poured the 58.44 g NaCl in, poured the remaining water up to the 1 L mark (being careful not to go over), and mixed it until it dissolved.
I mean, technically you'd be using slightly less than 1 L of water, because the container's containing the NaCl, too. But somehow, I don't think that's what the problem's asking.
And sure, the molar mass I got for NaCl (58.44 g) isn't exactly the same as the 58.5 stated in the problem, but I don't think that's it, either. If it was a significant figures question, I'd understand, but this is part of a Concentrations lab.
Am I missing something here?
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Am I missing something here?
You have not read the manual carefully.
There are two types of concentration: molar and molar, often confused because of the similarity in the name. In addition, for very low concentrations, the values of these concentrations are almost the same.
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molar and molar
Molar and molal :)
So wouldn't dissolving 58.44 g NaCl in 1 L H2O result in a 1 M NaCl solution, after all? I'm not seeing how it doesn't.
Hint: the density of 1 M solution is 1.0378 g/mL.
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molar and molar
Molar and molal :)
Unnoticed printing error - sometimes it happens, but it should happen as rarely as possible.
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I mean, technically you'd be using slightly less than 1 L of water, because the container's containing the NaCl, too. But somehow, I don't think that's what the problem's asking.
That is exactly what the problem's asking. That's why you make up a solution as they did on YouTube.
Note that a 1M solution is defined as 1 mole of solute in 1 L of solution (not 1 L of solvent).
Using Borek's density figure, 1 L of solution would contain 1038 g, of which 58 g is NaCl, so it only contains 980 g water.